What isperpendicular to y = –8x – 1, through (2, 3)?
A.y-10=1/8(x-4)
b y-10=-1/8(x-4)
c.y-10=-8(x-4)
d.y-4=-1/8(x-10)
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A.y-10=1/8(x-4)
b y-10=-1/8(x-4)
c.y-10=-8(x-4)
d.y-4=-1/8(x-10)
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Verified answer
A.
For a line to be perpendicular the slope must be the negative reciprocal of the first slope (ie -8/1 ==> +1/8)
And the point (2,3) exists on the line y-10 = 1/8(x-4) so A is the correct choice.