Xhulja
(x+3)²=16
x+3=4 or x+3=-4
x=1 or x=-7
x + 3 = ± 4
x = 1 , x = - 7
(x+3)² = 16
x+3 = ±√16 = ±4
x = -3±4 = -7, 1
16=4^2 or -4^2
(x+3)^2=4^2 or -4^2
so
(x+3)=4 or -4
x=4-3 or -4-3
(x+3)^2 = 4^2 or (x+3)^2 =(-4)^2
x+3 = 4 or -4
x =1 or x =-7
find square root of both sides to get
x+3=4 and x+3=-4
x=4-3 x=-4-3
x=1 x=-7
both values when replaced in the original equation give you the correct answer.
x ^2+6x+9=16
x ^2+6x-7=0
(x+7)(x-1)=0 x=-7 or x=1
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Xhulja
(x+3)²=16
x+3=4 or x+3=-4
x=1 or x=-7
x + 3 = ± 4
x = 1 , x = - 7
(x+3)² = 16
x+3 = ±√16 = ±4
x = -3±4 = -7, 1
16=4^2 or -4^2
(x+3)^2=4^2 or -4^2
so
(x+3)=4 or -4
x=4-3 or -4-3
x=1 or x=-7
(x+3)^2 = 4^2 or (x+3)^2 =(-4)^2
x+3 = 4 or -4
x =1 or x =-7
find square root of both sides to get
x+3=4 and x+3=-4
x=4-3 x=-4-3
x=1 x=-7
both values when replaced in the original equation give you the correct answer.
x ^2+6x+9=16
x ^2+6x-7=0
(x+7)(x-1)=0 x=-7 or x=1