Verified answer

y = 3x + 5

y = 2x - 10

set the two equations equal to each other, solving for x

3x + 5 = 2x - 10

3x - 2x = -10 - 5

x = -15

plug in x = -15 into one of the equations, solving for y

y = 2x - 10

y = 2(-15) - 10

y = -30 - 10

y = -40

solution:

x = -15

y = -40

A. (–15, –40)

In the future, to make questions like these clearer, you should use some sort of punctuation, such as a comma, to separate the two equations, like this:

y = 3x + 5, y = 2x - 10

Now, to solve the system, the first equation is already solved for y, so substitute 3x+5 for y in the second equation:

y = 2x - 10

3x + 5 = 2x - 10

x + 5 = -10

x = -15

Now plug that back into the first equation:

y = 3x + 5

y = 3(-15) + 5

y = -40

So, the solution is x = -15, y = -40, or in coordinate form, (-15,-40), which is choice A.

Hope that helps! :)