help
let (x1,y1)=(-1,13)
and (x2,y2)=(4,-2)
then slope of line from two given lines,m=(y2-y1)/(x2-x1)
putting above values , we get
=(-2)-(13)/(4)-(-1)
= -15/(4+1)
= -15/5
= -3
hence slope of line passing through given two point will be = -3
Slope is y2-y1 over x2-x1
You will set up your equation like this:
-2 - 13
over
4-(-1)
Your slope will be -15/5
Simplifies to -3
Slope = -3
The slope between two points is Îy/Îx
Îy/Îx = [13-(-2)] / [-1-4)] = (13+2) / (-5) = 15/ (-5) = -3
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Verified answer
let (x1,y1)=(-1,13)
and (x2,y2)=(4,-2)
then slope of line from two given lines,m=(y2-y1)/(x2-x1)
putting above values , we get
=(-2)-(13)/(4)-(-1)
= -15/(4+1)
= -15/5
= -3
hence slope of line passing through given two point will be = -3
Slope is y2-y1 over x2-x1
You will set up your equation like this:
-2 - 13
over
4-(-1)
Your slope will be -15/5
Simplifies to -3
Slope = -3
The slope between two points is Îy/Îx
Îy/Îx = [13-(-2)] / [-1-4)] = (13+2) / (-5) = 15/ (-5) = -3