6x + 3y = –9
3y = -6x – 9
y = -2x – 3
m1 = -2
perpendicular if m2 = -1/m1
slope m2 = -1/-2 = 1/2
First write the equation in the forma y = ax + b ... where a is the slope...
Then the equation is y = -2x - 3... here the slope is -2 ... a perpendicular line has a slope m so that
the product -2*m = -1 ==> then the slope of the perpendicular is 1/2 OK!
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6x + 3y = –9
3y = -6x – 9
y = -2x – 3
m1 = -2
perpendicular if m2 = -1/m1
slope m2 = -1/-2 = 1/2
First write the equation in the forma y = ax + b ... where a is the slope...
Then the equation is y = -2x - 3... here the slope is -2 ... a perpendicular line has a slope m so that
the product -2*m = -1 ==> then the slope of the perpendicular is 1/2 OK!