Supposing complete ionization:
NaCl → Na{+} + Cl{-} [two ions total]
(22.5 g NaCl) / (58.44 g NaCl/mol) x (2 mol ions / 1 mol NaCl) / (0.3750 kg) =
2.0534 mol ions / kg
(1.86°C/m) x (2.0534 m) = 3.8193°C change
0°C - 3.8193°C = - 3.82°C
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Verified answer
Supposing complete ionization:
NaCl → Na{+} + Cl{-} [two ions total]
(22.5 g NaCl) / (58.44 g NaCl/mol) x (2 mol ions / 1 mol NaCl) / (0.3750 kg) =
2.0534 mol ions / kg
(1.86°C/m) x (2.0534 m) = 3.8193°C change
0°C - 3.8193°C = - 3.82°C