Verified answer

(9.20 × 10^24 molecules)/(6.022 × 10^23 molecules/mol) = 15.28 mol.

The molar mass of methanol is 32.04 g/mol, so the mass is (32.04 g/mol)(15.28 mol) = 490. g (to 3 significant figures).

(9.04x10^24 molecules of CH3OH) X (a million mol CH3OH / Avogadro's quantity) X (Molar Mass of CH3OH / a million mol CH3OH) that's a ordinary stoichiometry concern. Avogadro's quantity is 6.022 x 10^23 ? There are that many molecules of CH3OH in a single mole, so which you will possibly use that as your ratio. Then, you alter it from moles to grams.