You can pull the 4 out from the square root, which would make it a 2 (since the square root of 4 is 2). Now 2 is a constant that you can pull out of the integral. This leaves you with √y, or y^1/2. Finally, we know the integral of a variable raised to any power (other than -1) will be (n^m+1)/(m+1). Of course we can't forget the constant, so the finally answer will follow the form 2*(n^m+1)/(m+1).
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((4y)^3/2)/3
You can pull the 4 out from the square root, which would make it a 2 (since the square root of 4 is 2). Now 2 is a constant that you can pull out of the integral. This leaves you with √y, or y^1/2. Finally, we know the integral of a variable raised to any power (other than -1) will be (n^m+1)/(m+1). Of course we can't forget the constant, so the finally answer will follow the form 2*(n^m+1)/(m+1).