What is the hydroxide concentration of a 0.10 molar solution of ammonia at equilibrium if its Ka is 5.62 × 10-?
A.) 1.33 × 10-2 molar
B.) 1.33 × 10-3 molar
C.) 3.17 × 10-12 molar
D.) 3.17 × 10-8 molar
E.) 7.50 × 10-6 molar
More Questions From This User See All
Answers & Comments
Verified answer
Kb=(10^-14)/Ka=1.779*19^-5.
c(NH3) is the analytical concentration of NH3
[OH-]=sqrt(c(NH3)*Kb)=sqrt( 0.1*1.779*10^-5)=1.33*10^-3
This is a crude approximation, in this case it has enough accuracy. The derivation of the formula above can be find online. If u want to know more, the book 'analytical chemistry' by Gary D Christian is recommended