To understand this, you have to first understand that you cannot get the square root of a negative number.
For example, √(-2) is not a real number. Why? Well, get ANY number you can think of. Now square it. You see that it's always positive (won't go in-depth as to why).
Now that you know that a radical can't be negative. Look at your problem.
-√(-5x-10).
I hope I don't lose you here, but the radical can only be 0 or a positive number. The negative in front of the radical changes all that. It suddenly makes the value 0 or a NEGATIVE number.
That means the value can only be 0 or lower. Therefore, 0 is the highest possible value.
hi, short answer: i anticipate you intend the entire expression 5x-10 is below the unconventional. if so C. 0 is the respond. If in basic terms the 5x is below the unconventional, then -10 is the biggest fee. info: y=-?(5x-10) as a results of unfavorable examine in front the sq. root image, the fee of the expression is unfavorable while the term interior the sq. root image is beneficial. that occurs while here difficulty happens: 5x-10 > 0 5x > 10 x>2 while x-2 ?(5(2)-10) = 0 For any selection decrease than 2 the term interior the unconventional sign will become unfavorable and the sq. root is imaginary. If the -10 isn't below the unconventional, the respond -10 would nicely be arrived at in a matching way. wish this facilitates. FE
the function gives negative answers, since squareroot can only give positive values
so if we are looking at the max value of this function, we have to actually look for the min value that this squareroot function can give, which is zero, at x = 2
Answers & Comments
Verified answer
Since the square root of any number is ≥ 0, you have that:
√(5x - 10) ≥ 0, for any x ≥ 2
When you multiply it by (-1) you get:
-√(5x - 10) ≤ 0, for any x ≥ 2
So y ≤ 0 and it has a maximum value when y = 0. This occurs when 5x - 10 = 0, so when x = 2.
The answer is zero.
To understand this, you have to first understand that you cannot get the square root of a negative number.
For example, √(-2) is not a real number. Why? Well, get ANY number you can think of. Now square it. You see that it's always positive (won't go in-depth as to why).
Now that you know that a radical can't be negative. Look at your problem.
-√(-5x-10).
I hope I don't lose you here, but the radical can only be 0 or a positive number. The negative in front of the radical changes all that. It suddenly makes the value 0 or a NEGATIVE number.
That means the value can only be 0 or lower. Therefore, 0 is the highest possible value.
hi, short answer: i anticipate you intend the entire expression 5x-10 is below the unconventional. if so C. 0 is the respond. If in basic terms the 5x is below the unconventional, then -10 is the biggest fee. info: y=-?(5x-10) as a results of unfavorable examine in front the sq. root image, the fee of the expression is unfavorable while the term interior the sq. root image is beneficial. that occurs while here difficulty happens: 5x-10 > 0 5x > 10 x>2 while x-2 ?(5(2)-10) = 0 For any selection decrease than 2 the term interior the unconventional sign will become unfavorable and the sq. root is imaginary. If the -10 isn't below the unconventional, the respond -10 would nicely be arrived at in a matching way. wish this facilitates. FE
0
the function gives negative answers, since squareroot can only give positive values
so if we are looking at the max value of this function, we have to actually look for the min value that this squareroot function can give, which is zero, at x = 2