The equation bearing on specific warmth to temperature substitute is Q = m*c*deltaT the place Q is your potential (a million.fifty seven kJ), m is the mass of your cloth (10.0g), c is the specific warmth of water (4.186 J/gC), and delta T is the substitute in temperature in celcius. you could now plug in those values, resolve for deltaT, and make certain the main suitable temp (i.e. 0 + deltaT).
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Verified answer
use H = mass x specific heat X change in temp
in this case that would mean
1470 J = 12 x 4.18 x (273- x)
1470 = 13693.7 -50.16x
-12223.7 = -50.16x
243.7 = final temp in kelvin
change back to C by subtracting 273
The equation bearing on specific warmth to temperature substitute is Q = m*c*deltaT the place Q is your potential (a million.fifty seven kJ), m is the mass of your cloth (10.0g), c is the specific warmth of water (4.186 J/gC), and delta T is the substitute in temperature in celcius. you could now plug in those values, resolve for deltaT, and make certain the main suitable temp (i.e. 0 + deltaT).