What is the equation of the line in slope-intercept form that passes through the point (3, –1) and is perpendicular to the line y = x + 1?
rancid has the right approach right up until the end, where he forgot to subtract 1 from the RHS:
y - (-1) = -1(x - 3)
y + 1 = -x + 3
y = -x + 2
the slope of: y = x + 1 is 1
the slope of the line perpendicular to the y = x + 1 is -1/1 = -1
the equation of the line in slope -1 that passes through the point (3, –1) is:
y - (-1) = -1(x-3) => y = -x +3
y=1/2x+5
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rancid has the right approach right up until the end, where he forgot to subtract 1 from the RHS:
y - (-1) = -1(x - 3)
y + 1 = -x + 3
y = -x + 2
the slope of: y = x + 1 is 1
the slope of the line perpendicular to the y = x + 1 is -1/1 = -1
the equation of the line in slope -1 that passes through the point (3, –1) is:
y - (-1) = -1(x-3) => y = -x +3
y=1/2x+5