Any two parallel lines always have the same slope. First we need to find the slope of given line.
2x-4 = y (slope intercept form y=mx+b)
slope(m) = 2
Now we have slope m=2 and point(-3,-11) to find new line.
Plugin x=-3 and y=-11 to get b value
So new line parallel to given line would have the equation as,
m = 2
y + 11 = 2 ( x + 3 )
y + 11 = 2x + 6
y = 2x - 5
Slop of the line = 2 as it is parallel to 2x-y =4.
Equation, (y+11) = 2(x+3),
y = 2x - 5.
Lines parallel to 2x-y=4 are of the form 2x-y=C for some real constant C.
If 2x-y=C passes through (-3, -11) then C = 2(-3)-(-11) = 5.
The equation of a line that passes through the point (-3,-11) and is parallel to the line whose equation is 2x-y=4 is 2x-y=5. ← ← ← ANSWER
In general, the line parallel to ax+by=c through a given point (x₀,y₀) is ax+by = ax₀+by₀.
2(-3) - ( - 11) = 5 ===> 2x - y = 5
Lines that are parallel will have the same coefficients for their variables.
2x - y = C
We know that when x = -3 , y = -11
2 * (-3) - (-11) = C
-6 + 11 = C
5 = C
2x - y = 5
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