What is the derivative of 3t^2/3 − 4t^1/3 + 7 ?
Can anybody help me out? I know that seven is zero because its a constant, but, I cant get the other two! Thanks!
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Can anybody help me out? I know that seven is zero because its a constant, but, I cant get the other two! Thanks!
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Verified answer
Bring down the exponent of x subtract one:
f'(x) = 3(2/3)t^(2/3-1) - 4(1/3)t^(1/3-1) + 0
f'(x) = 2t^(-1/3) - (4/3)t^(-2/3)
2t^(-1/3) - (4/3)t^(-2/3)