The equation of a circle is
(x - h)^2 + (y - k)^2 = r^2
Where
(h,k) is the center of the circle and r is the radius
(x - 3)^2 + (y + 3)^2 = 36
is the same as
(x - 3)^2 + (y - (-3))^2 = 6^2
So the center (h,k) = (3,-3)
The radius is 6
The equation of the circle with center (h, k) and radius r is (x - h)^2 + (y - k)^2 = r^2.
Center (3, –3), radius 6
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Verified answer
The equation of a circle is
(x - h)^2 + (y - k)^2 = r^2
Where
(h,k) is the center of the circle and r is the radius
(x - 3)^2 + (y + 3)^2 = 36
is the same as
(x - 3)^2 + (y - (-3))^2 = 6^2
So the center (h,k) = (3,-3)
The radius is 6
The equation of the circle with center (h, k) and radius r is (x - h)^2 + (y - k)^2 = r^2.
Center (3, –3), radius 6