If 0<θ< pi/2 (within the first quadrant), and 10 sin θ=n, what is tanθ in terms of n?
Draw the reference right triangle. Since 10 sin θ=n, then sin θ = n/10, meaning that the vertical leg has length n and the hypotenuse has length 10.
Using Pythagorean Theorem, you can find that the length of the opposite side must be sqrt(100 - n^2).
Thus, tan θ= n / sqrt(100 - n^2) or (in rationalize denominator form)
tan θ = n sqrt(100 - n^2) / (100 - n^2)
Draw a right triangle. It will help a lot.
no
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Verified answer
Draw the reference right triangle. Since 10 sin θ=n, then sin θ = n/10, meaning that the vertical leg has length n and the hypotenuse has length 10.
Using Pythagorean Theorem, you can find that the length of the opposite side must be sqrt(100 - n^2).
Thus, tan θ= n / sqrt(100 - n^2) or (in rationalize denominator form)
tan θ = n sqrt(100 - n^2) / (100 - n^2)
Draw a right triangle. It will help a lot.
no