What inequality is graphed?.
y > |x + 2| – 1
y < |x – 2| – 1
y > |x + 2| + 1
y < |x – 2| + 1
i think it is done this way
(1) y > |x + 2| – 1
gives two inequalities:
y +1 > x + 2
y > x+1
and y+1 < -x-2
y < -x-3
now what you do is plot the equations y=x+1 and y = -x-3
for the greater than equation mark(i.e shade or whatever ) everything above the line
and for the lesser than part do it below the line
now retain the shaded part which intersect in the above two graphs.
All the rest are plotted in the same way
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Verified answer
i think it is done this way
(1) y > |x + 2| – 1
gives two inequalities:
y +1 > x + 2
y > x+1
and y+1 < -x-2
y < -x-3
now what you do is plot the equations y=x+1 and y = -x-3
for the greater than equation mark(i.e shade or whatever ) everything above the line
and for the lesser than part do it below the line
now retain the shaded part which intersect in the above two graphs.
All the rest are plotted in the same way