Well, see, what you do first is to move the first x of the equation to the other side., so -2√x= -x. Next, you divide both sides by -2, so that √x= x/2. Now you square both sides, so that x = x squared/4. Once again move the 4 to the left side, giving you
4x = x squared. Now simply turn it into a quadratic equation. xsquared - 4x = 0. so, x ( x-4)=0, Once you get to this step, only look at the numbers in the parantheses, so x-4=0, and therefore x=4. I hope you were actually able to undestand that, it may have been a little confusing.
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Verified answer
First, x-2rad(x)=0
2) Subtract X from both sides.
-2rad(x) = -x
3) Divide -2 from both side.
rad(x) = -x / -2 (negatives cancel out x/2)
4) Square both sides to get rid of rad
x = x^2 / 4 (^ = sub script up)
5) multiply by 4 to each side
4x = x^2
6) divide x from both sides
4 = x^2 / x
(x^2 = x*x thus, x*x / x = x because x/x cancel out)
7) x = 4 :)
Plug it back in
4 - 2rad(4)=0
Rad(4)=2
4 - 2*2 = 0
Order of operations
4 - 4 =0
0=0 Check!@ yay
Well, see, what you do first is to move the first x of the equation to the other side., so -2√x= -x. Next, you divide both sides by -2, so that √x= x/2. Now you square both sides, so that x = x squared/4. Once again move the 4 to the left side, giving you
4x = x squared. Now simply turn it into a quadratic equation. xsquared - 4x = 0. so, x ( x-4)=0, Once you get to this step, only look at the numbers in the parantheses, so x-4=0, and therefore x=4. I hope you were actually able to undestand that, it may have been a little confusing.
4
Actually, the above answers are incorrect.
The two solutions are x=0 and x=4.
Remember your order of operations! It is crucial here!
If x=4:
4 - 2√4=0
4- 2(2)=0
4- 4=0
0=0
If x=0:
0- 2√0=0
0- 2(0)=0
0- 0=0
0=0
Therefore, x=0 and x=4.
Basically, you must either make both what precedes and follows the subtraction sign be the same. It's that simple!
I hope this helps and wish you all the best!
x = 4 or 0.
Think I got ..I used' /' as my root sign and ^ means squared.
x- 2 /x = 0
-2 /x = 0 + x
-2 = x + x^2 ....x squared
0 = x^2 + x + 2
x^2 + x + 2 = 0
(x + 2) (x - 1) = 0
x + 2 = 0.... equation (1)
x = - 2...answer (1)
x-1 = 0....eqaution (2)
x = 1 ....answer (2)
x = -2, 1...the two possible answers
either 0 or 4
x - 2√x = 0
=> x = 2√x
=> x^2 = 4x (applying sqaure on both sides)
=> x = 4 (dividing both sides by x)
I believe 0.
Because when you multiply any number (two times the square root of x) by zero, it equals zero.
So, zero minus two times the square root of zero equals zero.
It has been a few years since I took Calculus so check my work, but I think I am right.
Hope this helps!
2 (points, that is.)