A sequência (a, 4, b, 10) é inversamente proporcional a sequência (20, 10, 5, c). Qual é o valor de a + b+ c?
a----4-----b------10
20--10----5-------c
a.20=20a
4.10=40
b.5=5b
10.c=10c
20a=40
a= 40/20=2
5b=40
b=40/5=8
10c=40
c=40/10=4
a+b+c= 2+8+4=14
k(a, 4, b, 10)=(1/20,1/10,1/5,1/c)
4k=1/10 ==>k=1/40
ak=1/20 ==>a=2
bk=1/5 ==>b=8
10k=1/c ==>c=4
a+b+c=2+8+4=14
Ola carlos
20a = 4*10 = 5b = 10c
20a = 40
a = 2
5b = 40
b = 8
10c = 40
c = 4
a + b + c = 2 + 8 + 4 = 14
pronto
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Verified answer
a----4-----b------10
20--10----5-------c
a.20=20a
4.10=40
b.5=5b
10.c=10c
20a=40
a= 40/20=2
5b=40
b=40/5=8
10c=40
c=40/10=4
a+b+c= 2+8+4=14
k(a, 4, b, 10)=(1/20,1/10,1/5,1/c)
4k=1/10 ==>k=1/40
ak=1/20 ==>a=2
bk=1/5 ==>b=8
10k=1/c ==>c=4
a+b+c=2+8+4=14
Ola carlos
20a = 4*10 = 5b = 10c
20a = 40
a = 2
5b = 40
b = 8
10c = 40
c = 4
a + b + c = 2 + 8 + 4 = 14
pronto