Using Sum formulas for sine
sin (s + t) = sin s cos t + cos s sin t
we have
[Sin(A)Cos(π)]+[Cos(A)Sin(π)]
=[Sin(A) x (-1)]+[Cos(A)x0]
=-SinA
Denote* Cos(π)=-1,and Sin(π)=0
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Using Sum formulas for sine
sin (s + t) = sin s cos t + cos s sin t
we have
[Sin(A)Cos(π)]+[Cos(A)Sin(π)]
=[Sin(A) x (-1)]+[Cos(A)x0]
=-SinA
Denote* Cos(π)=-1,and Sin(π)=0