V = 25 Sin 100 πt using calculus determine the mean range t=0 to t=10milli seconds?
If you use mean value=2/pie x max value. the answer comes to 15.92mA.
Update:Cheers for your answer but your method doesn't come out at 15.92mA. more help required please
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d V/ dt = 25 d (sin 100πt / 100 π t * d π t/dt
= -25 cos 100 πt * π *1
= -25 π cos 100 πt
= - 25 π cos 100 πt
= - 25 * 3.14 cos 100 *π*t
= - 78.5 cos 100 *π* 0 [When t= 0]
= -78.5 Cos 0 = -78.5 *1
= -78.5...............................1) 1st condition.
dV/dt= -25 π cos 100 π t
= - 25 π cos 100 π * (10 /1000) [ when t= 10 ms =10 /1000]
= -25 π cos 100 π* .01
= - 25πcos π
= - 78.5 *-1
= 78.5 ..........................2) 2nd condition
Note: dV/dt is an accleration.