Olá!
Estou com dificuldade de resolver:
f (x) = x²+1/x-1
Agradeço aos que me responder.
Derivada do quociente:
f(x) = a(x) / b(x)
f'(x) = [a'(x) . b(x) - a(x) . b'(x)] / [b(x)]²
............................................................................
f(x) = (x² + 1) / (x - 1)
f'(x) = [(x² + 1)' . (x - 1) - (x² + 1) . (x - 1)'] / (x - 1)²
f'(x) = [2x . (x - 1) - (x² + 1) . 1] / (x - 1)²
f'(x) = (2x² - 2x - x² - 1) / (x - 1)²
f'(x) = (x² - 2x - 1) / (x - 1)²
Ola Mezaque
f(x) = g(x)/h(x)
derivada de um quociente
(g/h)' ´= g'*h - g*h')/h²
g = x² + 1
g' = 2x
h = x - 1
h' = 1
f'(x) = (2x*(x - 1) - )x² + 1)*1))/x- 2)²
f'(x) = 2x² - 2x - x² - 1)/(x - 2)² = (x² - 2x - 1)/(x - 2)²
pronto
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Verified answer
Derivada do quociente:
f(x) = a(x) / b(x)
f'(x) = [a'(x) . b(x) - a(x) . b'(x)] / [b(x)]²
............................................................................
f(x) = (x² + 1) / (x - 1)
f'(x) = [(x² + 1)' . (x - 1) - (x² + 1) . (x - 1)'] / (x - 1)²
f'(x) = [2x . (x - 1) - (x² + 1) . 1] / (x - 1)²
f'(x) = (2x² - 2x - x² - 1) / (x - 1)²
f'(x) = (x² - 2x - 1) / (x - 1)²
Ola Mezaque
f(x) = g(x)/h(x)
derivada de um quociente
(g/h)' ´= g'*h - g*h')/h²
g = x² + 1
g' = 2x
h = x - 1
h' = 1
f'(x) = (2x*(x - 1) - )x² + 1)*1))/x- 2)²
f'(x) = 2x² - 2x - x² - 1)/(x - 2)² = (x² - 2x - 1)/(x - 2)²
pronto