It's you again! ...the one who does not know the "order of operations." VERY IMPORTANT. What you typed means sqrt(A) + (1/sqrt(B)) - 1, when I believe you meant was
[sqrt(A) + 1]/[sqrt(B) - 1].
Any time you replace a horizontal fraction bar with a diagonal slash, you are likely to need symbols of inclusion to show what was originally in the numerator and what was originally in the denominator.
Anyway, tan(75) = tan(30 + 45)
= [tan(30) + tan(45)] / [1 - tan(30)tan(45)]
= [1/sqrt(3) + 1] / [1 - 1/sqrt(3)];
now multiply all 4 terms by square root of 3, obtaining:
Answers & Comments
It's you again! ...the one who does not know the "order of operations." VERY IMPORTANT. What you typed means sqrt(A) + (1/sqrt(B)) - 1, when I believe you meant was
[sqrt(A) + 1]/[sqrt(B) - 1].
Any time you replace a horizontal fraction bar with a diagonal slash, you are likely to need symbols of inclusion to show what was originally in the numerator and what was originally in the denominator.
Anyway, tan(75) = tan(30 + 45)
= [tan(30) + tan(45)] / [1 - tan(30)tan(45)]
= [1/sqrt(3) + 1] / [1 - 1/sqrt(3)];
now multiply all 4 terms by square root of 3, obtaining:
[1 + sqrt(3)]/[sqrt(3) - 1].