Verified answer

(x+y)²=x²+2xy+y²

(x-y)²=x²-2xy-y²

x²-10x+25=x²-2xy+y²

x²=x² E -10x=-2xy<=>(-2).5x=-2xy<=>5x=xy<=>y=5 E 25=y² <=> y=5

121=11²

x²-10x+25 =121

<=> (x-5)²=11²

<=> x-5=11

<=> x=16

:)

x²-10x+25=121

x²-10x+25-121=0

x²-10x-96=0

∆=(-10)²-4(1)(-96)=

100+384=484

√484=22

x=(10±22)/2

x'=-12/2=-6

x"=32/2=16

Resolve por Bháskara.

x² - 10x + 25 = 121

X² - 10x - 96 = 0

A = 100 + 4 . 96

A= 484

x' = 10 + 22 / 2

x' = 16

x' ' = 10 - 22 /2

x' ' = - 6