logab C / logab A = 4 - logab A
Não consigo terminar, me ajudem!!
Se não conseguirem ver direito é o exercício 4 do link abaixo:
http://www.infoescola.com/matematica/logaritmo/exe...
loga(b) = 3
logab(c) = 4
log(b)/log(a) = 3
log(c)/(log(a) + log(b)) = 4
log(c) = 4*(log(a) + log(b))
log(c)/log)a) = 4*log(a)/log(a) + 4*log(b)/log(a)
loga(c) = 4 + 4*3 = 4 + 12 = 16 (B)
pronto
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Verified answer
loga(b) = 3
logab(c) = 4
log(b)/log(a) = 3
log(c)/(log(a) + log(b)) = 4
log(c) = 4*(log(a) + log(b))
log(c)/log)a) = 4*log(a)/log(a) + 4*log(b)/log(a)
loga(c) = 4 + 4*3 = 4 + 12 = 16 (B)
pronto