Two point charges are on the y-axis. A 2.5 µC charge is located at y = 1.45 cm.?
Also, a -2.08 µC charge is located at y = -1.90 cm.
(a) Find the total electric potential at the origin.
(b) Find the total electric potential at the point having coordinates (1.50 cm, 0).
I have followed the professors guidelines on how to solve this problem and have not come anywhere close to solving this problem. The feedback on web assign stated that I was getting significantly different answers. Help!
More Questions From This User See All
Answers & Comments
Verified answer
OK . I think I can give you a method to follow. First, recall the superposition theorem. The electric field at the origin will be the sum of the individual fields of the charges.
So
a)
Eo = E1 + E2
From Coulombs law,
E1 = q1 / (4* pi* eo* r1^2) where q1 = 2.5 uC = 2.5 * 10^(-6) C and r1 = 1.45 cm = 0.0145 m
E2 = q2 / (4 * pi * eo * r2^2) where q2 = - 2.08 uC = - 2.08 * 10^(-6) C and r2 = 1.9 cm = 0.019 m
I'll let you plug the numbers in.
b) For this part, you can use Pythagoras to work out the distance from each charge to the point 0.015m along the x-axis, then use the method above to find the total E-field at that point.
Try this and see what you get now. Good luck!