Two identical charges q = (1/9.0) × 10−9 C are shown in the figure below. Find the potential at P. (Take r =?
Two identical charges q = (1/9.0) × 10−9 C are shown in the figure below. Find the potential at P.
(Take r = 1.17 m and θ = 38°.)
http://imgur.com/XVHLw
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The potential is kq1/r + kq2/r
The angle doesn't even matter because "r" is the straight line distance from q to P
For both charges q, that distance is r = 1.17m
See the reference
kq = (1/9)*10^9 * 9*10^9 = 1 and 1/r =0.854
0.854 + 0.854 = 1.71V