Trig math help angle θ between vectors?
1.)Find the angle θ between the vectors.
u =(6, 8)
v =(-3, 0)
2.)Find the angle θ between the vectors.
u = 9j
v = -2i
3.)Find the angle θ between the vectors.
u = 2cos(2π/3) i + 2sin(2π/3) j
v = 5cos(π/4) i + 5sin(π/4) j
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Verified answer
1.) (6, 8) • (-3, 0)/√[(6^2 + 8^2)((-30)^2 + 0^2)] = (-18 + 0)/(10 • 30) = -18/300 = -0.06
93.43981... ≈ 93°