Verified answer

The two negative charges on the same side as the positive charge will have equal forces in opposite directions so will cancel out. So you only need to worry about the 3rd charge.

The distance of this charge from the positive charge is the height (altitude) of the equilateral triangle

= 22cm * sin(60 degrees)

= 22cm * sqrt(3) / 2

So now you've got the magnitude of the two charges and the distance between them, so you can work out the force. (Using the formula, which I forget but will be in your text book). The direction of the force will be towards this 3rd negative charge, because opposite charge attract.

each and all the unfavorable quotes will exert an alluring stress on the helpful can charge. If the helpful can charge is placed on the midpoint of an ingredient, the forces from the adjoining corners will cancel one yet another out. so which you purely might desire to evaluate the gorgeous stress of the unfavorable can charge on the some distance nook. The length of the median of an equilateral triangle is s*sqrt(3)/2, the place s is the size of an ingredient. so as that could charge is at a distance of twenty-two*sqrt(3)/2 = 19.05 cm. remedy for the electrostatic stress (in Coulombs) F = ok*q1*q2 / r^2, the place ok is the Coulomb consistent (approx 9 x 10^9 N*m^2/C^2), q1 and q2 are the magnitudes of the electric powered quotes (in C), and r is the gap between them (in m).