The rms current in a 44-Ω resistor is 0.59 A. What is the peak value of the voltage across this resistor?
E = IR
E = 0.59 x 44 = 25.96 volts RMS
Vp = √2 * Vrms = √2*25.96 = 36.7 volts
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Verified answer
E = IR
E = 0.59 x 44 = 25.96 volts RMS
Vp = √2 * Vrms = √2*25.96 = 36.7 volts