The rate of the reaction 2 A(g) + 3 B(g) + 5 C(g) → is found to be independent of the concentration of A?
, first order in the concentration of B, and second order in the concentration of C. When 5.23 moles of A, 5.2 moles of B, and 5.87 moles of C are placed in a 2 liter con- tainer, the initial rate of the reaction is found to be 0.072 mol/liter· sec.
What is the numerical value of the reaction rate constant in units of moles, liters, and seconds?
Answer in units of M−2 · s−1
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rate = k x [A]⁰ x [B]¹ x [C]² = k x [B]¹ x [C]²
then..
.. k = rate / ([B]¹ x [C]²) = (0.072M/sec) / ([2.6M]¹ x [2.94M]²) = __ / (M² sec)
you get to finish
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if you're wondering where 2.6 and 2.94 came from...
.. m = moles / liter = 5.2 moles / 2 Liters = ?