The mass of a star is 1.570×1031 kg and it performs one rotation in 20.50 days. Find its new period (in days)?
The mass of a star is 1.570×1031 kg and it performs one rotation in 20.50 days. Find its new period (in days) if the diameter suddenly shrinks to 0.510 times its present size. Assume a uniform mass distribution before and after
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Angular momentum is conserved and varies with the square of the radius. Ergo, the period also varies with the radius squared:
T' = T * 0.510² = 5.332 days