The blade of a windshield wiper moves through an arc of 90° in a time of 0.40s. The tip of the blade moves?
The blade of a windshield wiper moves through an arc of 90° in a time of 0.40s. The tip of the blade moves on the arc of a circle that has a radius of 0.45m. What is the magnitude of the centripetal acceleration of the tip of the blade? Hint: A circle is made up of 4 angles of 90.
a) 6.9 m/s2b) -6.9 m/s2c) 110.9 m/s2d) -110.9 m/s2
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First, convert the degrees into radians: 90 degrees = pi/2 radians
Now, we calculate its angular velocity (w):
w = pi/2 radians /0.40 seconds = 1.25 pi radians/second
Centripetal acceleration = v^2/r = rw^2
Substituting values in:
a = 0.45 (1.25pi)^2
= 6.94...
=6.9 m/s^2 (2s.f.)