The angular position of a swinging door is described by π = 5.01 + 9.7t + 1.97t2 rad. Determine the angular position, angular speed, andΒ ?
The angular position of a swinging door is described by π = 5.01 + 9.7t + 1.97t^2 rad. Determine the angular position, angular speed, and angular acceleration of the door at
(a) t = 0
Β ____ rad
Β ____ rad/s
Β ____ rad/s2
(b) t = 3.10 s
Β ____ rad
Β ____ rad/s
Β ____ rad/s2
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Verified answer
(a) t = 0:
theta = 5.01 rad,
angular speed = (9.7 + 3.94 t) rad/s = 9.7 rad/s,
angular acceleration = 3.94 rad/s^2.
(b)Β t = 3.10 s:
theta = (5.01 + 9.7*3.10 + 1.97*3.10^2) rad/s = use calculator!
angular speed = (9.7 + 3.94*3.10) rad/s = use calculator;
angular acceleration = 3.94 rad/s^2.