The altitude of the helicopter is 2800 m.
tan(35) = 2800/x
xtan(35) = 2800
x = 3998.81 m or 3999 m answer//
Using the tangent ratio for a right angle triangle it is: 2800/tan(35) = 3,998.814419 or about 4,000 m
Horizontal distance D from buoy to ship is given by 2800/D = tan 35°, ie., D = [2800/tan35°](m)
= 3998.814419(m), approx = 4000(m).
Let x be the horizontal distance from the buoy to the ship.
(2800 m)/x = tan(35 deg) =>
x = 4.0 km
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
tan(35) = 2800/x
xtan(35) = 2800
x = 3998.81 m or 3999 m answer//
Using the tangent ratio for a right angle triangle it is: 2800/tan(35) = 3,998.814419 or about 4,000 m
Horizontal distance D from buoy to ship is given by 2800/D = tan 35°, ie., D = [2800/tan35°](m)
= 3998.814419(m), approx = 4000(m).
Let x be the horizontal distance from the buoy to the ship.
(2800 m)/x = tan(35 deg) =>
x = 4.0 km