then r is an integer
if X - r divides f(X) then f(r) = 0
indeed
f(X) = (X - r)Q(X) (remainder is 0)
f(r) = (r - r)Q(r) = 0
a0 + a1r ... + r^n = 0
a1r ... + r^n = - a0 (*)
if r is not integer and it is rational, also all of its powers were not integer,
even if all a_i (i=1,..n-1) simplifies with r^i giving integer result in (*)
r^n is not integer and cannot be equal to - a0 which is integer
his is absurd so r must be integer
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Verified answer
if X - r divides f(X) then f(r) = 0
indeed
f(X) = (X - r)Q(X) (remainder is 0)
f(r) = (r - r)Q(r) = 0
a0 + a1r ... + r^n = 0
a1r ... + r^n = - a0 (*)
if r is not integer and it is rational, also all of its powers were not integer,
even if all a_i (i=1,..n-1) simplifies with r^i giving integer result in (*)
r^n is not integer and cannot be equal to - a0 which is integer
his is absurd so r must be integer