suppose Θ is an angle......................?
in standard position whose terminal side lies in Quadrant II.
if sin Θ = 12/13, find the value of sec Θ.
answer choices:
a. -5/13
b. -13/5
c. -12/5
d. 13/12
e6q13
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Verified answer
sin(θ) = 12/13
cos²(θ) + sin²(θ) = 1
cos²(θ) = 1 - sin²(θ)
cos²(θ) = 1 - (12/13)²
cos²(θ) = (13²/13²) - (12²/13²)
cos²(θ) = (13² - 12²)/13²
cos²(θ) = (169 - 144)/13²
cos²(θ) = 25/13²
cos²(θ) = 5²/13² → you know that θ is located in the quadrant II → cos(θ) < 0
cos(θ) = - 5/13 → you know that: sec(x) = 1/cos(x)
sec(θ) = - 13/5
→ answer B
I would say b.