sin t=
cost=
csc(-t)=
sect=
sin(t+2pi)=
please show work and explain. thank you.
Quadrant IV is between 270º and 360º
tan[t] = -1 ⁄ (0.9) ... cot[t] = 1 ⁄ tan[t]
t = tan‾¹[-1 ⁄ (0.9)] = -48º or -48 + 360 = 312º
t = 312º = 312 • (π ⁄ 180) = 5.445 radians
The rest can be done with a calculator:
Working in radians ...
sin[5.445] = -0.743
cos[5.445] = 0.669
csc[5.445] = 1 ⁄ sin[5.445] = -1.345
sec[5.445] = 1 ⁄ cos[5.445] = 1.5
sin[t + 2π] = sin[t] = -0.743 ... repeats every 2π radians
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Verified answer
Quadrant IV is between 270º and 360º
tan[t] = -1 ⁄ (0.9) ... cot[t] = 1 ⁄ tan[t]
t = tan‾¹[-1 ⁄ (0.9)] = -48º or -48 + 360 = 312º
t = 312º = 312 • (π ⁄ 180) = 5.445 radians
The rest can be done with a calculator:
Working in radians ...
sin[5.445] = -0.743
cos[5.445] = 0.669
csc[5.445] = 1 ⁄ sin[5.445] = -1.345
sec[5.445] = 1 ⁄ cos[5.445] = 1.5
sin[t + 2π] = sin[t] = -0.743 ... repeats every 2π radians