SOMEBODY PLEASE HELP! Two small, identical particles have charges Q1=+3.0 μC and Q2=-5.0 μC. If the electric f?
Two small, identical particles have charges Q1=+3.0 μC and Q2=-5.0 μC. If the electric force between the particles is 120 N, what is the difference between the particles
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The equation you will use is:
Kc (q*q/ r^2) = F
Kc=Coulomb's constant=8.99 * 10^9 N m^2/q^2.
Plug in everything, switch the F and the r^2 then take the square root of both sides. EXPONENTS!!!!! The biggest problem my students have with this chapter is the scientific notation and how exponents are to be handled. Double check your work because these are easy to make careless mistakes on.
2 element costs lie alongside the y axis. A charge of q a million = -13.ZeroµC is at y = 7.0 m,and a cost of q 2 = -4.0 µC is at y = -4.0 m. detect the element (particularly than infinity) at whichthe finished electric self-discipline is 0. Y =