Making 'a' the subject of the equation: a = + or - the square root of (5n+7)/D
Same answer I gave you last time you asked this exact same question
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5n = Da² - 7
Add 7 to both sides
5n + 7 = Da²
Divide both sides by D
(5n + 7) / D = a²
a² = (5n + 7)/ D
Take the square root of both sides
a = ±√ [ (5n + 7) / D ] D ≠ 0
5n + 7 = D a²
± √((5n + 7) / D) = a
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Making 'a' the subject of the equation: a = + or - the square root of (5n+7)/D
Same answer I gave you last time you asked this exact same question
-----------------------------
5n = Da² - 7
Add 7 to both sides
5n + 7 = Da²
Divide both sides by D
(5n + 7) / D = a²
a² = (5n + 7)/ D
Take the square root of both sides
a = ±√ [ (5n + 7) / D ] D ≠ 0
5n = Da² - 7
5n + 7 = D a²
(5n + 7) / D = a²
± √((5n + 7) / D) = a