(a) Move the constant term to the right side of the equation.

(b) Multiply each term in the equation by four times the coefficient of the x^2 term.

(c) Square the coefficient of the original x term and add it to both sides of the equation.

(d) Take the square root of both sides.

(e)Set the left side of the equation equal to the positive square root of the number on the right side and solve for x.

(f) Set the left side of the equation equal to the negative square root of the number on the right side of the equation and solve for x.

My equation is 4x^2 – 4x - 3 = 0

I get stuck at (d) and this is what I have:

(a) 4x2 – 4x - 3 (+3) = 0(+3) (move the constant term to the right side of the equation)

(b) 4x2 – 4x = 3 (4 times the coefficient of 4x2 =16) which is 64x2 – 64x = 48

(c) 64x2 – 64x = 48 (square the coefficient of the original x term and add it to both sides of the equation)

64x2 – 64x + 16 = 48 + 16

64x2 – 64x + 16 = 64

(d) 64x2 – 64x + 16 = 64 (take the square root of both sides)

(8x – 4)2 = 8

Any help understanding this is much appreciated!