(3/x+y+1) - (2/2x-y+3) = 6/12
(2/x+y+1 + 3/2x-y+3) = 1
comecei multiplicando o de cima por 2 e o de baixo por 3 pra excluir o "a" ... mas pelo visto estava errado ...
Ola łαvi
3/(x + y + 1) - 2/(2x - y + 3) = 6/12
2/(x + y + 1) + 3/(2x - y + 3) = 1
seja A = 1/(x + y + 1) e B = 1/(2x - y + 3)
6A - 4B = 1
2A + 3B = 1
6A + 9B = 3
13B = 2
B = 2/13
2A = 1 - 3B
2A = 1 - 6/13 = 7/13
A = 7/26
x + y + 1 = 26/7
2x - y + 3 = 13/2
7x + 7y + 7 = 26
4x - 2y + 6 = 13
7x + 7y = 19
4x - 2y = 7
14x + 14y = 38
28x - 14y = 49
42x = 87
x = 87/42 = 29/14
2y = 4x - 7
2y = 4*29/14 - 7
2y = 58/7 - 49/7
2y = 9/7
y = 9/14
S = { (x,y), (29/14, 9/14) }
pronto
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Answers & Comments
Ola łαvi
3/(x + y + 1) - 2/(2x - y + 3) = 6/12
2/(x + y + 1) + 3/(2x - y + 3) = 1
seja A = 1/(x + y + 1) e B = 1/(2x - y + 3)
6A - 4B = 1
2A + 3B = 1
6A + 9B = 3
13B = 2
B = 2/13
2A = 1 - 3B
2A = 1 - 6/13 = 7/13
A = 7/26
x + y + 1 = 26/7
2x - y + 3 = 13/2
7x + 7y + 7 = 26
4x - 2y + 6 = 13
7x + 7y = 19
4x - 2y = 7
14x + 14y = 38
28x - 14y = 49
42x = 87
x = 87/42 = 29/14
2y = 4x - 7
2y = 4*29/14 - 7
2y = 58/7 - 49/7
2y = 9/7
y = 9/14
S = { (x,y), (29/14, 9/14) }
pronto