√(x^2+2x+1)
=√x^2+x+x+1 (you can write 2x as x+x)
=√x(x+1)+1(x+1) (from x^2+x i took x common)
=√(x+1)(x+1)
=√(x+1)^2 (^2 and square root will cancel out resulting in (x+1) as shown below)
=(x+1) Answer
Factorise the quadratic:
â(x + 1)(x + 1)
Notice how the two sets of brackets are identical, so combine them:
â(x + 1)^2
The combination of the square root and square exponent cancel each other out:
(x + 1)
(X+1) (X+1)
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√(x^2+2x+1)
=√x^2+x+x+1 (you can write 2x as x+x)
=√x(x+1)+1(x+1) (from x^2+x i took x common)
=√(x+1)(x+1)
=√(x+1)^2 (^2 and square root will cancel out resulting in (x+1) as shown below)
=(x+1) Answer
Factorise the quadratic:
â(x + 1)(x + 1)
Notice how the two sets of brackets are identical, so combine them:
â(x + 1)^2
The combination of the square root and square exponent cancel each other out:
(x + 1)
(X+1) (X+1)