Verified answer

(9-6i)-(12+2i)=

collect reals and imaginaries:

(9-12)-6i-2i=-3-8i

a million. cope with as vector addition (12, -6i) + (3, 8i) = (15, -2i) = 15 - 2i 2. (6+i) * (8-3i) = 40 8 + 8i - 18i - 3i² = 40 8 + 8i - 18i + 3 = fifty one - 10i 3. 2 * SQRT[ x - 8 ] = 6, SQRT[ x - 8 ] = 3, x - 8 = 9, x = 17 4 SQRT[ x + 14 + 2 ] = SQRT[ x + sixteen ] = x, x² - x - sixteen = 0 by utilising the quadratic formulation, x = a million/2 ± a million/2 * SQRT[ a million + sixty 4 ] = a million/2 ± a million/2 * SQRT[ sixty 5 ]

(9 - 6i) - (12 + 2i)

Distribute the -1 into 12 and 2i to get:

9 - 6i - 12 - 2i

Group into like terms:

9 - 12 - 6i - 2i

Solve:

-3 - 8i

(9-6i)-(12+2i)

=(9-6i)-12-2i

=9-6i-12-2i

=9-12-6i-2i

=-3-8i

Multiply the negative in the middle with the numbers in the bracket.

negative multiply negative gives positive and positive multiply negative gives negative. Positive multiply positive gives positive. in another words

(-)*(-)=(+)

(-)*(+)=(-)

(+)*(+)=(+)

then i suppose you know how to simplify from there.

Multiply the negative to the second

pair of parenthesis.

Then, Just take away the parenthesis,

and match the same terms,

the real numbers with the real

numbers,

the imaginaries, with the imaginaries.

So yep.