Thank you in advance. The answer is 1/cos^2θ
1 + tan²θ
Use the Pythagorean Identity, which says 1 + tan²x = sec²x:
= sec²θ
Remember that secx = 1/cosx so that would mean that sec²x = 1/cos²x:
= 1 / cos²θ
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1 + tan²θ
Use the Pythagorean Identity, which says 1 + tan²x = sec²x:
= sec²θ
Remember that secx = 1/cosx so that would mean that sec²x = 1/cos²x:
= 1 / cos²θ