f(x) = ax² + bx + c
f(2x + 3) = a(2x+3)² + b*(2x + 3) + c
a*(4x² + 12x + 9) + 2bx + 3b + c = 2x² - 4x +1
4a = 2
a = 1/2
6x + 2bx = - 4x
2b = -10
b = -5
9a + 3b + c = 1
9/2 - 15 + c = 1
c = 16 - 9/2 = 23/2
f(x) = (x² - 10x + 23)/2
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Verified answer
f(x) = ax² + bx + c
f(2x + 3) = a(2x+3)² + b*(2x + 3) + c
a*(4x² + 12x + 9) + 2bx + 3b + c = 2x² - 4x +1
4a = 2
a = 1/2
6x + 2bx = - 4x
2b = -10
b = -5
9a + 3b + c = 1
9/2 - 15 + c = 1
c = 16 - 9/2 = 23/2
f(x) = (x² - 10x + 23)/2
pronto