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Consider the function f(x)=x^2=6x-2. h,Find the x-coordinate of the vertex of this parabola
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Consider the function f(x)=x^2=6x-2. h,Find the x-coordinate of the vertex of this parabola
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Assuming you mean f(x) = x^2 + 6x - 2
f(x) = x^2 + 6x + (6/3)^2 - 2 - (6/3)^2
f(x) = (x + 3)^2 - 11
Vertex's x-coordinate is -3.