(x + y)² = x² + y² + 2xy
x² + y² = (x + y)² - 2xy = 1² - 2*(-1/2) = 1 + 1 = 2
(x² + y²)/xy = 2/(-1/2) = -2*(2/1) = -4
pronto
vamos la
(x+y)=1 elevando ambos os termos ao quadrado
x²+2xy+y²= 1
x²+y²= 1-2xy
x²+y²= 1-2(-1/2)
x²+y²= 1+1
x²+y²= 2
(x²+y²)/xy = 2/(-1/2) = -4 okkkkk
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Verified answer
(x + y)² = x² + y² + 2xy
x² + y² = (x + y)² - 2xy = 1² - 2*(-1/2) = 1 + 1 = 2
(x² + y²)/xy = 2/(-1/2) = -2*(2/1) = -4
pronto
vamos la
(x+y)=1 elevando ambos os termos ao quadrado
x²+2xy+y²= 1
x²+y²= 1-2xy
x²+y²= 1-2(-1/2)
x²+y²= 1+1
x²+y²= 2
(x²+y²)/xy = 2/(-1/2) = -4 okkkkk