help
x² - 3√3x + 6 = 0
delta
d² = 27 - 24 = 3
d = √3
x1 = (3√3 + √3)/2 = 2√3
x2 = (3√3 - √3)/2 = √3
pronto
a = 1
b = -3√3
c = 6
Δ = b² - 4ac
Δ = (-3√3)² - 4 × 1 × 6
Δ = 9 × 3 - 4 × 1 × 6
Δ = 27 - 24
Δ = 3
x = (-b ± √Δ) / 2a
x = (3√3 ± √3) / 2 × 1
x = (3√3 ± √3) / 2
x' = (3√3 - √3) / 2
x' = 2√3 / 2
x' = √3
x'' = (3√3 + √3) / 2
x'' = 4√3 / 2
x'' = 2√3
S = {√3 , 2√3}
Espero ter ajudado!
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Verified answer
x² - 3√3x + 6 = 0
delta
d² = 27 - 24 = 3
d = √3
x1 = (3√3 + √3)/2 = 2√3
x2 = (3√3 - √3)/2 = √3
pronto
x² - 3√3x + 6 = 0
a = 1
b = -3√3
c = 6
Δ = b² - 4ac
Δ = (-3√3)² - 4 × 1 × 6
Δ = 9 × 3 - 4 × 1 × 6
Δ = 27 - 24
Δ = 3
x = (-b ± √Δ) / 2a
x = (3√3 ± √3) / 2 × 1
x = (3√3 ± √3) / 2
x' = (3√3 - √3) / 2
x' = 2√3 / 2
x' = √3
x'' = (3√3 + √3) / 2
x'' = 4√3 / 2
x'' = 2√3
S = {√3 , 2√3}
Espero ter ajudado!