a) log[2](2-x) - log[4](17-x) = 1
b) log[x+7]25 = log[2]4
log4( (2-x)² ) - log4(17-x) = log4(4)
(2 - x)²/(17 - x) = 4
x² - 4x + 4 = -4x + 68
x² = 64
x = 8 não serve
x = -8
log[x+7](25) = log2(4)
log(25)/log(x+7) = 2
log(25) = 2*log(x+7)
log(5²) = log((x + 7)²)
x + 7 = 5
x = -2
pronto
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Verified answer
a) log[2](2-x) - log[4](17-x) = 1
log4( (2-x)² ) - log4(17-x) = log4(4)
(2 - x)²/(17 - x) = 4
x² - 4x + 4 = -4x + 68
x² = 64
x = 8 não serve
x = -8
log[x+7](25) = log2(4)
log(25)/log(x+7) = 2
log(25) = 2*log(x+7)
log(5²) = log((x + 7)²)
x + 7 = 5
x = -2
pronto